Problem |
Solution |
1) At a slug race, the fastest slug traveled 10 inches per hour, but it had to rest for 30 minutes every 3 feet. At this record setting pace, how long will it take the slug to travel 8
feet?
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1. If the slug rests 30 minutes every 3 feet then it rests 2 times in a 8-foot race.
2. Convert the slug's 'speed' to feet/hour = 10/12 = .8333 ft/hr.
3. Multiply the slug's speed by the distance and
    add the rest times = 8 ft. / 0.833 ft/hr + 2 (30 min) =
    9.6 hr + 1 hr. = 10.6 hours. = 10 hours 36 min.
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2) Elevators at the Space Needle travel at the same speed as raindrops, 10 miles per hour. The elevator ride takes about 40 seconds. How far, to the nearest foot, will the elevator travel? Note: 5280 feet = 1 mile
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1. Convert the elevator's speed to feet/hour =
    10 mi./hr. = 5280 x 10 = 52800 ft/hr.
2. Convert the elevator ride time to hours =
    40/3600 = 0.0111 hours.
3. Muliply this by the time of the elevator ride =
    52800 x 0.01111 = 586.67 feet.
4. Rounded = 587 ft.
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3) Sam cuts a piece of wire 64 centimeters in length into two parts. The parts are then each bent to form a square. The total area of the two squares is 130 square centimeters.
How much larger is a side of the larger square than a side of the smaller square? The sides of each square are in whole number lengths.
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This is actually an algebra problem with 2 equations and 2 unknowns
Call the two side lengths a and b.
- First equation:    4a + 4b = 64 cm.
- Second equation:    a2 + b2 = 130 sq. cm.
- First equation reduced by dividing by 4: a + b = 16
- First equation as expression for a: a = 16 - b
- Substitute in the second equation:
(16 - b)2 + b2 = 130 sq. cm.
256 - 32b + b2 + b2 = 130
2b2 - 32b + 126 = 0
b2 - 16b + 63 = 0
- Using the quadratic formula:
    b = 16 ± √256 +4(63)     = 8 ± 1 = 9 or 7                   2
- So b is 9 or 7 and a is 7 or 9
- The larger side is 2 cm. longer than the shorter side
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