4) A company manufactures washers that are supposed to be 2 mm thick. In reality they will accept washers that are within 1 mm of the 2 mm target. The company buys a new machine to produce
these washers. Out of the first 100 washers it produces, the median thickness is 2.5 mm, the range is 3.9 mm, the first quartile median is 1.8 mm, and the third quartile median is 3 mm. The thickest washer had a thickness of 5 mm. From this data at least how many washers of the 100 washers did not meet the company's requirements?
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- If the range is 3.9 mm and the thickest washer is 5 mm, the the minimum thickness was 5 - 3.9 = 1.1 mm.
- The median is 2.5 mm, so all the washers below the median are acceptable.
- If the median of the third quartile (the one just above the whole set median) was 3 mm (the upper limit) it is possible that all the third quartile washers were acceptable if all of them above the median were 3 mm thick (unlikely)
- This means that all the washers in the 4th quartile were unacceptable (their thicknesses were above 3 mm.), therefore the least number of washers that did not meet the company's criteria was 25 washers of the 4th quartile.
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5) Joan and David invent a probability game for a homework project that has players flip a fair coin and roll a fair 6 sided number cube with the numbers 1 through 6 on it. David moves ahead on the game board as many spaces as the number that comes up on the number cube when the coin lands on heads. Joan moves ahead three spaces when the coin lands on tails no matter what number comes up on the cube. After 2 rolls and flips what's the probability that David will have moved 8 spaces?
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- The number of possible outcomes is
(2x6) x (2x6) = 144
- The only outcomes that can produce a move of 8 spaces are when David rolls a head both times, which is 1⁄4 of the possibilities = 36 possibilities
- Of those 36 possibilities here are the dice combinations that produce 8 spaces:
- 2+6
- 3+5
- 4+4
- 5+3
- 6+2
- So the probability of David moving 8 spaces is 5/144
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