Problem |
Solution |
1) Study the sequence of shapes below built out of squares. How many squares would be in the nth term of the sequence?
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Let n = the term number (1, 2, 3, ...)
- The top row is 3n
- The bottom vertical squares are n
- The ones in between are n(n-1)
- So the total number of squares in the nth term is:
    3n + n + n(n-1) =
    4n + n2 - n =
    3n + n2
- Test this on the first 3:
    for n=1: 3+1 = 4
    for n=2: 6+4 = 10
    for n=3: 9+9 = 18 It works!
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2) What is the next term in this sequence:
    1, 2, 2, 4, 8, 32, 256, __
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Each term is the product of the previous 2 terms, so the next term is 256 x 32 = 8192
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3) What is the 8th term in the following sequence?
    0th     SOHCAHTOA
    1st     AOTHACHOS
    2nd     AOHACHOS
    3rd     SOHCAHOA
    4th     SOCAHOA
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- The input sequence with some spaces to clarify:
    0th     SOHCAHTOA
    1st     AOTHACHOS
    2nd     AO   HACHOS
    3rd     SOHCAHOA
    4th     SO   CAHOA
- The sequence is
1st term: reverse term 0
2nd term: remove 3rd letter
3rd term: reverse term 2
4th term: remove 3rd letter
- Continuing this pattern:
5th term: reverse term 4         AOHACOS
6th term: remove 3rd letter    AOACOS
7th term: reverse term 6         SOCAOA
8th term: remove 3rd letter:   SOAOA
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