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Solution |
1) Jessica is camping with her family and needs to get water for the camp. She needs 11⁄2 gallons.
She has a pot that holds 5/8 gallon. The spring where she gets water is 1/5 mile from camp. How many miles will she walk while getting the water using only the 5/8 gallon pot? Express your
answer as a mixed number.
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- Each round trip is 2⁄5 of a mile.
- She needs 11⁄2 = 12⁄8 gallons
- 12⁄8 ÷ 5⁄8 = 12/5 = 2, remainder 2, so it takes 3 trips =
3 x 2⁄5 = 11⁄5 mile
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2) The prime factors of one number are 2, 3, and 7. A second number has the prime factors 2, 7, and 11. If their least common multiple is 9702 what is the smallest the first number could be?
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- 2x3x7 = 42 and 2x7x11 = 154 and 42x154= 6468, which is less than 9702 so clearly one of the prime factors (or more) are repeated in the first number.
- For the first number to be a minimum, we must investigate multiple 2s and 3s first.
- Try 2 2s:
2x2x7x3 = 84;   9702/84 = 115.5, so this doesn't work
Try 3 2s:
2x2x2x7x3 = 168;   9702/168 = 57.75, so this doesn't work either.
- Try 2 3s:
2x7x3x3 = 126; 9702/126 = 77, so this works!
- The first number is 126 and the second 77:
    126 x 77 = 9702
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3) At the summer carnival there is a game of chance. You pay $5.00 to play a single game. A game consists of one toss at the target. If you hit the target you win $11.00. If you miss you get $0.00. What is the fewest number of games you can play and break even? (Meaning the carnival didn't gain or lose any money to you).
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This is a least common multiple (lcm) problem.
- What is the lcm of 5 and 11? 5x11 = 55
- However many games you play, let's call it N, you pay $5xN to play
- In order to break even you must win W of those games to equal $5 x N
- $11 x W must equal $5 x N, therefore both W and N must be factors of 55.
- The only value for N that this is true is 11
because $5 x 11 = $11 x 5.
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