5) Four friends have their birthdays in the same month. This year the squares containing
their birthdates on the calendar touch each other such that they make a larger square.
Two of their birthdates are multiples of six. The horizontal sums and the vertical sums are
prime. What is the sum of the four birthdates? |
OK, a tough problem! The place to start is with the horizontal sums of 2 consecutive days of the month that add to a prime number. Here they are:
    (1+2) (2+3) (3+4) (5+6) (6+7) (8+9) (9+10) (11+12)
    (14+15) (15+16) (18+19) (20+21) (21+22) (23+24)
    (26+27) (28+29) (29+30) (30+31)
2. Now, with this list, the dates under the pairs are these dates +7, so write out the pairs (one pair above the other) that fit this requirement:
  (1+2)    (8+9) |
  (2+3)    (9+10) |
  (8+9)  (15+16) |
  (11+12)    (18+19) |
  (14+15)    (21+22) |
  (21+22)    (28+29) |
  (23+24)    (30+31) |
3. Select out of this list those that add vertically to primes:
  (2+3)    (9+10) |
  (11+12)    (18+19) |
4. Finally, Select out of this list those in which 2 of the 4 dates are multiples of 6:
  (11+12)    (18+19) |
5. Sum the 4 dates = 11+12+18+19 = 60
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