Hands-on math!

Washington State Math Olympiad
Hints and Solutions
2012 Grade 8 Measurement

Problem
Solution
1) Four year old Tyrol sleeps 10 hours and 30 minutes each day. If he does that for a whole year that is 365 days long, how long is that to the nearest minute expressed in days, hours, and minutes?
  1. 10.5 x 365 = 3832.5 hours of sleep
  2. 3832.5/24 = 159.6875 days
  3. .6875 day = 16.5 hours
  4. .5 hour = 30 minutes.
  5. So he slept for 159 days, 16 hours and 30 minutes

2) The dimensions of a gaming room are 10 feet by 17 feet by 11 feet. A spider and a fly are both in the room. What is the furthest distance they could be apart to the nearest tenth of a foot?
The longest distance they can be from each other is from an upper corner of the room to the lower opposite corner.
  1. Find the diagonal length of the 10x17 floor:
    By the pythagorean theorem:
    d = √ (102+ 172 = 19.72 feet
  2. Find the diagonal length from the ceiling to the opposite corner of the floor:
    d = √ (112+ 19.722 = 22.6 feet
3) Mario is driving in Canada at a steady rate of 100 km/hr. His twin sister, Daneka, is driving at a steady rate of 70 mph in Washington. Who is faster and by how much? Express your answer in mph. Note 1 mile = 1.609 kilometers. 100 km x 1 mile = 62.15 mph
    hour     1.609 km
Daneka is faster by 70 - 62.15 = 7.85 mph.
Note: We had to use the inverse of the conversion factor to get the units to cancel properly

Problem
Solution
4) Donte is mowing his lawn. The front wheels of the mower are 5 inches in diameter and the back wheels are 8 inches in diameter. Donte begins by pushing the mower for 48 feet along the front edge of his lawn. How many more rotations will each front wheel make than each back wheel over the 48 feet? Round your answer to the nearest tenth of a rotation.
  1. The circumference of the larger wheel is 8
  2. The circumference of the smaller wheel is 5
  3. Over 48 feet, the larger wheel will make 48x12/8 = 22.93 revolutions
  4. Over 48 feet, the smaller wheel will make 48x12/5 = 36.69 revolutions
  5. The front wheel makes 36.69 - 22.93 = 13.7 more revolutions

5) Suppose it were always true that 7 cats can catch 7 mice in 7 minutes. How many cats would it take to catch 100 mice in 50 minutes?
  1. It takes 7 minutes for 1 cat to catch a mouse.
  2. So, in 50 minutes 1 cat can catch 50/7 = 717 mice
  3. So to catch 100 mice would take
    100/(717) = 14 cats