Problem |
Solution |
1) The distance around a track is 1/4 mile. Jessie plans to run 5 miles and has already done 6 laps.
How many more laps must she run to complete 5 miles?
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1. Compute the number of laps in 5 miles =
    5/(1/4) = 5 x 4 = 20 laps.
2. Subtract the laps she has already done. Remaining =
    20 - 6 = 14 laps.
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2) At the end of February Jenny noticed that she could finally get up when it was light in the
morning. She kept track of when sunrise was for a few days in the paper and saw a pattern:
Feb 24, 2013 | 6:59 AM |
Feb 25, 2013 | 6:57 AM |
Feb 26, 2013 | 6:55 AM |
Feb 27, 2013 | 6:53 AM |
If the pattern holds true, when was sunrise on February 1st? |
1. Find the amount of time the sunrise advances for 1 day = 2 min.
2. Compute the number of days from Feb 1st to the 24th = 23 days. Remember, don't count the 24th!
3. Multiply this by the number of minutes the time advances in one 1 day =
    23 x 2 = 46 minutes.
4. Compute the time of sunrise on the 1st, going forward this number of minutes =
    6:59 am + 46 minutes = 7:45 AM.
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3) The figure shows a sequence of castle
fronts made from cubes. The number of
cubes needed for each castle front form a
numerical pattern. How many cubes are
needed for the castle front of Castle 8?
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1. This is actually 2 sequences added together.
2. The first sequence is the number of cubes on the top of each castle (a constant) = 2 cubes.
3. The second sequence is the number of cubes making the remainder of the castle front. Write out that sequence =
    N = 1   2   3
    # = 3   8   15
4. For each castle, N, then this second sequence is
    N x (N+2)
5. Compute the number of cubes in the 8th castle as the number of cubes in the first sequence + the number of cubes in the remainder, using N = 8 =
    2 + 8 x (8 + 2) = 2 + 8 x 10 = 82 total cubes.
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