4) Jeremy baked a cake. Sue cut the cake into equal-sized pieces and took one piece. Nathan
took 1/5 of the remaining pieces. Finally, Jeremy took 1/3 of the remaining pieces. If 1/2 of the
cake is still remaining, how many pieces did Sue cut the cake into? |
Work this problem backwards:
1. If Jeremy took 1/3 of the remaining pieces (X) and that left 1/2 of the cake, then the amount of the cake that was there before Jeremy was
    X - (1/3)X = 1/2.
    (2/3)X = 1/2
    X = 3/4 of the cake.
2. If Nathan took 1/5 of the remaining pieces (Y) and that left 3/4, then:
    Y - (1/5)Y = 3/4
    (4/5)Y = 3/4
    Y = 15/16 of the cake.
3. Then, what's left, (1 - 15/16) = 1/16th of the cake.
Sue cut the cake into 16 pieces.
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