Problem |
Solution |
1) The sum of four consecutive integers is 74. What is the largest of these numbers?
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Let N be the largest number.
Then the sum is
    N - 3 +
    N - 2 +
    N - 1 +
    N =         74
Turn this into an equation and solve for N:
    (N - 3) + (N - 2) + (N - 1) + N = 74
    4N - 6 = 74
    4N = 80
    N = 20
    The consecutive integers are 17, 18, 19 and 20.
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2) 4/5 + (1+3+5+7)/(1*3*5*7) = ?
(Express your answer as a fraction in lowest terms) |
1. Perform the division = 16/105
2. Convert the fraction to the other fraction's denominator and add = 4/5 = 84/105 + 16/105 = 100/105 = 20/21
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3) The average of five numbers is 42. If 4 is added to the first number, 5 is added to the second number, 6 is added to the third number, and so on, what will the new average be?
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1. Add the added numbers together = 4 + 5 + 6 + 7 + 8 = 30
2. Take 5 X the average and add this sum to it and divide by 5 =
    (5 x 42 + 30)/5 = (210 + 30)/5 = 240/5 = 48.
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