Olympiad Common Problems - 6th Grade

1). Problem type: Find missing number of a list given the average.
Example:
After three tests Max has a test average of 83. He is nervous for the fourth test and wants to keep an average of at least 80. What is the lowest score he can get on the fourth test if each test is worth 100 points?
Solution:
1. Let N be the 4th score.
2. Let N3 be the sum of the first 3 tests.
    N3 = _____
3. The equation for the average is:
    (N3 + N) / 4 = 80.
3. Solve this equation for N:


    N = ____.
2). Problem type: Areas of composite shapes
Example:
How many square yards of synthetic turf are needed to cover the interior of the track shown? The ends of the track are semicircles.
Solution:
1. Since the width of the track is 8 yards and the ends of the track are semicircles, the radius of those ends is ____ yds.
2. Compute the area of 2 of these semicircles = _____ sq. yds.
3. Compute the area of the interior of the track = _____ sq. yds.
4. Add these 2 measurements together and round to the nearest tenth of a sq. yd.


    Total area = _____ sq. yds.
3.) Problem type: Arithmetic sequence:
Example:
Pictured is a sequence of growing chairs. The first chair is made of 6 squares. How many squares are in the 20th chair?
Solution:
1. Write the number of squares under each chair.
2. Determine D, the number of squares added to each chair.
    D = ___
3. The equation for the nth term of an arithmetic sequence is:
    An = A1 + D (n - 1), where:
    A1 is the first term
    An is the nth term (the one you're looking for)
4. Write out the equation with the parameters of this problem and solve for A20:


    A20 = _____

4). Problem type: Solving 2 simultaneous equations
Example:
Parmveer has a bag with 54 coins. Altogether the coins are worth $4.75. He only has nickels and dimes in the bag. How many dimes are in the bag?
Solution:
Use N for the number of nickels and
    D for the number of dimes.
1. The equation for the number of coins:
    N + D = 54
2. The equation for the sum of the coins:
    5N + 10D = 475
3. Write an expression for N using the first equation and then substitute it in the second equation and solve.



    N = _____
    D = _____
5). Problem type: Permutations
Example:
Roxanne is ordering a pizza. She can choose from 3 sizes, 3 types of crust, 4 blends of sauce, and 6 toppings. How many pizza combinations are possible if she orders a pizza with 2 toppings?
Solution:
First, remember that these are combinations where
    the order of selecting toppings doesn't count.

1. How many ways can she choose a size = ___
2. How many ways can she choose a crust = ___
3. How many ways can she choose a sauce = ___
4. How many ways can she choose that first topping? ____
5. After she chooses that first topping, how many ways can she choose the second topping? = ___
6. Total choices of toppings = ____
7. Since order of toppings doesn't count, take half of the topping choices = _____
8. Multiply these together = _____
6.) Problem type: Working a problem backwards
Example:
Quint bought a car. He sold it to Rachael for 5/6 of the price he paid for it. Rachael sold it to Shawn for 1/5 less than she paid for it. Shawn sold it to Teddy for 3/4 of what he paid. Teddy paid $1200 for it. How much did Quint pay for it originally?
Solution:
Use Q for Quint, R for Rachael, S for Shawn and T for Teddy.
Start at the bottom:
1. If Teddy paid $1200 for the car and it was 3/4
    of what Shawn paid, then 1200 = (3/4) x S.
    So S = ______
2. Rachael sold it to Shawn for 4/5 of what she paid Quint for it, so
    (4/5) R = S, and R = ____.
3. Continue this logic until you solve for Q:


    Q = _____

7). Problem type: Turning words into equations:
Example:
Jane bought a 36 inch rope of licorice to share with her brother Andy. She gave Andy a piece that is three inches more than half the length of her piece. How long is Andy's piece of licorice?
Solution:
Let J = length of Jane's piece.
Let A = the length of Andy's piece.
1. Then the expression for Andy's piece is
    "3 inches more than half of Jane's piece" =
    ___________________.
2. Make an equation that adds Jane's and Andy's pieces and sets them equal to the whole length = _______________________.
3. Solve for Andy's piece:


    A = ____
8). Problem type: Cartesian coordinates
Example:
1) A parallelogram has vertices at
(0, 0), (5, 2), and (1, 3).
The fourth vertex has positive coordinates. What are they?
Solution:
l. Plot the 3 points on the graph.
2. Since the opposite sides of a parallelogram are parallel, the third vertex and the 4th vertex are parallel to the first and second.
3. The offset of the second vertex from the first is (___,___).
4. Apply this offset to the third vertex to find the 4th = (___,___).