3)
There are ten jelly beans in a sack. Four are mint flavored, three are celery flavored, two are licorice flavored, and the last is peanut butter flavored. Nyang, who doesn't like
peanuts, but loves celery, reaches in and grabs two jelly beans and eats them without looking. What is the probability that one was celery flavored, and the other was not peanut flavored?
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- Method 1: Brute force!
The jellybeans are (each one is numbered) where
C=celery, M=mint, L=licorice and P=peanut:
C1 C2 C3 M1 M2 M3 M4 L1 L2 P
Here are the possibilities: (the ones that have a celery (Cn) and not a peanut (P) are marked with an *)
C1 C2*
C1 C3*
C1 M1*
C1 M2*
C1 M3*
C1 M4*
C1 L1*
C1 L2*
C1 P
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C2 C3*
C2 M1*
C2 M2*
C2 M3*
C2 M4*
C2 L1*
C2 L2*
C2 P
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C3 M1*
C3 M2*
C3 M3*
C3 M4*
C3 L1*
C3 L2*
C3 P
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M1 M2
M1 M3
M1 M4
M1 L1
M1 L2
M1 P
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M2 M3
M2 M4
M2 L1
M2 L2
M2 P
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M3 M4
M3 L1
M3 L2
M3 P
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M4 L1
M4 L2
M4 P
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L1 L22
L1 P
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L2 P
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There are a total of 45 possibilities of which 8+7+6 = 21 of them have a celery and not a peanut for a probability of 21/45 = 7/15
- Method 2: Count the combinations:
- The total number of combinations of 10 things taken 2 at a time is
(10 x 9)/2 = 45
- With each of the celery jellybeans, there are 8 + 7 + 6 = 21 possible combinations that do not include a peanut flavored bean.
- Therefore the probability is 21/45 = 7/15
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